Re: Allocating memory with "new"

On Apr 23, 8:00 pm, "sk_usenet" <sometechyguy at gmail dot com> wrote:
> "Pat" <pkelecy@[EMAIL PROTECTED]
> wrote in message
> >I have a question about the new operator.  The syntax for it is:
>
> > int * pointer = new int;
>
> > which says that "pointer" points to a type int variable.
>
> > My question is why is "int" needed twice?  I know it's needed from a
> > syntax standpoint, but I don't understand what additional information
the
> > second int really provides.  Doesn't the first int already tell you
that
> > an int type value is going to be stored at the "pointer" address?
>
> What about arrays?
>  int *p = new int[10];
>
> > Can you ever have,
>
> > int * pointer = new double
>
> No, realize that new operator is returning a double*, and heance trying
to
> assign to an int* is not legal.
>
> > or something like that?
> > Thanks for any feedback on this.
>
> --http://techytalk.googlepages.com

never mind. You use "int" to store pointer. This trick will be work
for 32 bit platforms because size of any pointer will be 4 bytes. But
for 64 bit platforms you will have a problem, because size of any
pointer will be more than 4 bytes. You can see note also about pointer
to int conversion when compiling.