Pat said:
<snip>
> But to clarify a comment you made, if I have a structure, say:
>
> struct coordinateDefinition
> {
> float x;
> float y;
> float z;
> }
>
> and use that to define the structure,
>
> coordinateDefinition point1={1.5,2.3};
>
> then by default, point1.z=0?
This is certainly true in C, because IF you initialise AT LEAST ONE of the
members of an aggregate object (e.g. a struct or an array), any that you
don't initialise take on their default static initialisation values (0 for
integer types, NULL for pointers, 0.0 for doubles, and recursively for
aggregates). Whether it's true in C++, I'm not certain.
> So you don't have to explicitly define all
> the members?
You don't have to explicitly *initialise* all the members, no.
> What if z were a char type instead?
<shrug> It would gain the value '\0' (i.e. a null character).
--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www.
+rjh@[EMAIL PROTECTED]
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"Usenet is a strange place" - dmr 29 July 1999
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