Hal Vaughan wrote:
> Philip Potter wrote:
>
>> Ben Bacarisse wrote:
> ...
>> Indeed. To the OP: how did you manage to state that parseargs() had two
>> different declarations? You should *never* type code into a usenet
>> message - copy-and-paste instead, so that the code you post is exactly
>> the same as the code you're using.
>
> You're right. I knew better, but was a bit fuzzy and probably should
not
> have been posting at 3:00 am, but it was a case of, "If I can get this
one
> thing done, I can go to bed knowing it's resolved." I'm still out of it
> (from lack of sleep) now, so maybe I should just put this on the shelf
for
> a bit and take a break.
>
>> From the other message you've posted, I conclude you don't realise
that
>> the [] in a parameter is significant. The following:
>>
>> int main(int argc, char *argv)
>>
>> is incorrect, while both of:
>>
>> int main(int argc, char *argv[])
>> int main(int argc, char **argv)
>>
>> are correct and completely equivalent..
>
> So
>
> char *argv[]
> and
> char **argv
>
> are essentially the same?
They are *exactly* the same in a parameter list.
Elsewhere the difference is clear - one is an array of 'char *'s, and
one is a pointer to a 'char *'.
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