Re: Total Newbie Backward Compat Question

Chris ( Val ) wrote:

> On Mar 12, 1:35 am, Hal Vaughan <h...@[EMAIL PROTECTED]
> wrote:
>> First, thanks to all who replied with any comments.  It's a big help!
> 
> [snip]
> 
>> > Close! std::cout isn't actually a function, but an object. Yes, it's
in
>> > the std namespace. And yes, std::endl is in there too. In each case,
>> > the object in question belongs to a class in which the << operator
has
>> > been overloaded (forget it - you *don't* want to know, at least not
for
>> > another few weeks).
>>
>> Don't worry, I'm used to overloading and use it frequently in Java.
> 
> No, I think you're confused :-)
> 
> There is a difference between "function or method overloading" as
> opposed to "operator overloading", which Java does not offer, and
> is what is spoken of above.

I just looked it up.  Yes, big difference!  Thanks for catching that!

....
>> Oh, and is there any reason you specify std::cout and suggest using
>> std::foo for most functions when needed instead of using using
namespace
>> std?
> 
> [snip]
> 
> Yes, it is the most restrictive and safest way to access objects in C+
> +.
> 
> Look up namespaces in your favourite book - Most books should cover
> them
> adequately these days.

Every book I've looked at and each web page I've seen in my source, except
for one, uses "using namespace std" instead of std:: for many objects.

Hal