Dave Balderstone <dave@[EMAIL PROTECTED]
> wrote:
> In article <2008042815593316807-phantom@[EMAIL PROTECTED]
>, Phantom
> <phantom@[EMAIL PROTECTED]
> wrote:
>
> > I'm wondering if anyone here knows of an elegant way to eliminate
> > duplicate values from an applescript list.
> >
> > e.g. taking this list:
> > {"apple", "orange", "apple", "watermelon", "orange"}
> >
> > and returning
> > {"apple", "orange", "watermelon"}
> >
> >
> > not a big priority, but it would help with one of my scripts. could't
> > find a answer with google, unfortunately, sorry to bother if this
comes
> > up a lot.
> >
> > thanks guys.
>
> Try this:
>
> set list1 to {"apple", "orange", "apple", "watermelon", "orange"}
> set list2 to {"apple", "orange", "watermelon"}
> set list3 to {}
>
> repeat with x from 1 to count of items of list1
> set n to item x of list1
> if n is in list2 and n is not in list3 then set end of list3 to n
> end repeat
>
> return list3
Sorry Dave but I've modified your code because I think that the original
post relates to a situation where there is only one list. If this is the
case then you need:
on run
set list1 to {"apple", "orange", "apple", "watermelon", "orange"}
set list2 to {}
repeat with x from 1 to count of items of list1
set n to item x of list1
if n is not in list2 then set end of list2 to n
end repeat
return list2
end run
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